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38.7=4x^2-36x
We move all terms to the left:
38.7-(4x^2-36x)=0
We get rid of parentheses
-4x^2+36x+38.7=0
a = -4; b = 36; c = +38.7;
Δ = b2-4ac
Δ = 362-4·(-4)·38.7
Δ = 1915.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-\sqrt{1915.2}}{2*-4}=\frac{-36-\sqrt{1915.2}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+\sqrt{1915.2}}{2*-4}=\frac{-36+\sqrt{1915.2}}{-8} $
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